Statement I A charged capacitor is disconnected from a battery. Now if its plates are separated further, the potential energy will fall. Statement II Energy stored in a capacitor is equal to the work done in charging it.

Question

Statement I A charged capacitor is disconnected from a battery. Now if its plates are separated further, the potential energy will fall. Statement II Energy stored in a capacitor is equal to the work done in charging it. (A) Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement I. (B) Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement I. (C) Statement I is correct but Statement II is incorrect. (D) Statement I is incorrect but Statement II is correct.

Tardigrade Admin · Accepted Answer

Battery is disconnected from the capacitor, So, Q= constant Energy =(Q2/2 C)=(Q2 d/2 ε0 A) ⇒ Energy propto d

Q. Statement I A charged capacitor is disconnected from a battery. Now if its plates are separated further, the potential energy will fall.
Statement II Energy stored in a capacitor is equal to the work done in charging it.

Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement I.

Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement I.

Statement I is correct but Statement II is incorrect.

Statement I is incorrect but Statement II is correct.

Battery is disconnected from the capacitor,
So, $Q =$ constant
Energy $= \frac{Q ^{2}}{2 C} = \frac{Q ^{2} d}{2 ε _{0} A}$
$\Rightarrow$ Energy $\propto d$

Q. Statement I A charged capacitor is disconnected from a battery. Now if its plates are separated further, the potential energy will fall. Statement II Energy stored in a capacitor is equal to the work done in charging it.