Statement-1: ∼(p rightarrow∼ q) is equivalent to p ↔ q. Statement-2: ∼ (p ↔ ∼ q) is a tautology.

Question

Statement-1: ∼(p rightarrow∼ q) is equivalent to p ↔ q. Statement-2: ∼ (p ↔ ∼ q) is a tautology. (A) Statement-1 is true, Statement-2 is true; Statement-2 is a correct explanation for Statement-1 (B) Statement-1 is true, Statement-2 is true; Statement-2 is not a correct explanation for Statement-1 (C) Statement-1 is true, Statement-2 is false (D) Statement-1 is false, Statement-2 is true

Tardigrade Admin · Accepted Answer

Correct answer is (c) Statement-1 is true, Statement-2 is false

Q. Statement-1 : ∼(p↔∼q) is equivalent to p↔q. Statement-2 : ∼(p↔∼q) is a tautology.

Statement-1 is true, Statement-2 is true; Statement-2 is a correct explanation for Statement-1

Statement-1 is true, Statement-2 is true; Statement-2 is not a correct explanation for Statement-1

Statement-1 is true, Statement-2 is false

Statement-1 is false, Statement-2 is true

Correct answer is (c) Statement-1 is true, Statement-2 is false

Q. Statement-1 : $\sim (p \leftrightarrow\sim q)$ is equivalent to $p \leftrightarrow q$ .
Statement-2 : $\sim (p \leftrightarrow\sim q)$ is a tautology.