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  4. Statement-1: ∼(p rightarrow∼ q) is equivalent to p ↔ q. Statement-2: ∼ (p ↔ ∼ q) is a tautology.

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Q. Statement-1 : $\sim\left(p\,\leftrightarrow\sim q\right) $ is equivalent to $p ↔ q$.
Statement-2 : $\sim \left(p\, ↔ \sim q\right)$ is a tautology.

AIEEEAIEEE 2009Mathematical Reasoning

Solution:

Correct answer is (c) Statement-1 is true, Statement-2 is false

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