Statement 1: Recent convention to represent Kp is dimensionless. Statement 2: The standard state of pure gas is 1 bar and the partial pressure of reactants and products measured with respect to this standard are used to determine Kp for the equilibrium. A(g)+2B(g)→ C(g)

Question

Statement 1: Recent convention to represent Kp is dimensionless. Statement 2: The standard state of pure gas is 1 bar and the partial pressure of reactants and products measured with respect to this standard are used to determine Kp for the equilibrium. A(g)+2B(g)→ C(g) (A) If both Statement 1 and Statement 2 are true and the statement 2 is the correct explanation o f the statement 1 . (B) Ifboth Statement 1 and Statement 2 are true but statement 2 is not the correct explanation o f the statement 1 . (C) If Statement 1 is true but Statement 2 is false. (D) If Statement 1 is false but Statement 2 is true.

Tardigrade Admin · Accepted Answer

Let partial pressure of reactants and products are a, b, c bar respectively with respect to standard state, then

A (g) + 2 B (g) \to C (g)

P_{A} = \frac{aba r}{1 ba r} = 1

Similarly

P_{B} = b

and

P_{c} = 0

Thus,

K_{p} = \frac{c}{a \times b ^{2}}

is dimension less.

Q. Statement 1: Recent convention to represent Kp​ is dimensionless. Statement 2: The standard state of pure gas is 1 bar and the partial pressure of reactants and products measured with respect to this standard are used to determine Kp​ for the equilibrium. A(g)+2B(g)→C(g)

If both Statement 1 and Statement 2 are true and the statement 2 is the correct explanation o f the statement 1 .

Ifboth Statement 1 and Statement 2 are true but statement 2 is not the correct explanation o f the statement 1 .

If Statement 1 is true but Statement 2 is false.

If Statement 1 is false but Statement 2 is true.

Let partial pressure of reactants and products are a, b, c bar respectively with respect to standard state, then A(g)+2B(g)→C(g) PA​=1barabar​=1 Similarly PB​=b and Pc​=0 Thus, Kp​=a×b2c​ is dimension less.

Q. Statement 1: Recent convention to represent $K_{p}$ is dimensionless.
Statement 2: The standard state of pure gas is 1 bar and the partial pressure of reactants and products measured with respect to this standard are used to determine $K_{p}$ for the equilibrium.
$A (g) + 2 B (g) \to C (g)$

Let partial pressure of reactants and products are a, b, c bar respectively with respect to standard state, then
$A (g) + 2 B (g) \to C (g)$
$P_{A} = \frac{aba r}{1 ba r} = 1$
Similarly $P_{B} = b$ and $P_{c} = 0$
Thus, $K_{p} = \frac{c}{a \times b ^{2}}$ is dimension less.