Statement 1:Oxidation number of carbon in CH2O is zero. Statement 2:CH2O formaldehyde, is a covalent compound.

Question

Statement 1:Oxidation number of carbon in CH2O is zero. Statement 2:CH2O formaldehyde, is a covalent compound. (A) If both Statement 1 and Statement 2 are true and the statement 2 is the correct explanation of the statement 1. (B) Ifboth Statement 1 and Statement 2 are true but statement 2 is not the correct explanation of the statement 1. (C) If Statement 1 is true but Statement 2 is false. (D) If Statement 1 is false but Statement 2 is true.

Tardigrade Admin · Accepted Answer

Both statements are true but statement 2 is not the correct explanation of statement 1. Oxidation number can be calculated using some rules. H is assigned +1 oxidation state and O has oxidation number-2

∴

O. No. of C in

C H_{2} O :

O. no. of

C + 2 (+ l) + (- 2) = 0

∴

O. No. of

C = 0

Q. Statement 1:Oxidation number of carbon in CH2​O is zero. Statement 2:CH2​O formaldehyde, is a covalent compound.

If both Statement 1 and Statement 2 are true and the statement 2 is the correct explanation of the statement 1.

Ifboth Statement 1 and Statement 2 are true but statement 2 is not the correct explanation of the statement 1.

If Statement 1 is true but Statement 2 is false.

If Statement 1 is false but Statement 2 is true.

Both statements are true but statement 2 is not the correct explanation of statement 1. Oxidation number can be calculated using some rules. H is assigned +1 oxidation state and O has oxidation number-2 ∴ O. No. of C in CH2​O: O. no. of C+2(+l)+(−2)=0 ∴ O. No. of C=0

Q. Statement 1:Oxidation number of carbon in $C H_{2} O$ is zero.
Statement 2: $C H_{2} O$ formaldehyde, is a covalent compound.

Both statements are true but statement 2 is not the correct explanation of statement 1. Oxidation number can be calculated using some rules. H is assigned +1 oxidation state and O has oxidation number-2
$∴$ O. No. of C in $C H_{2} O :$
O. no. of $C + 2 (+ l) + (- 2) = 0$
$∴$ O. No. of $C = 0$