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Q. Statement 1:Oxidation number of carbon in $CH_{2}O$ is zero.
Statement 2:$CH_{2}O$ formaldehyde, is a covalent compound.

Redox Reactions

Solution:

Both statements are true but statement 2 is not the correct explanation of statement 1. Oxidation number can be calculated using some rules. H is assigned +1 oxidation state and O has oxidation number-2
$\therefore $ O. No. of C in $CH_{2}O:$
O. no. of $C + 2 (+ l) + ( - 2) = 0$
$\therefore $ O. No. of $C = 0$