Statement 1: On cooling a freezing mixture, colour of the mixture turns to pink from deep blue for a reaction. Co(H2O)2+6(aq)+4Cl-(aq)leftharpoons CoCl2-4(aq)+6H2O(l) Statement 2: Reaction is endothermic so on cooling, the reaction moves to backward direction

Question

Statement 1: On cooling a freezing mixture, colour of the mixture turns to pink from deep blue for a reaction. Co(H2O)2+6(aq)+4Cl-(aq)leftharpoons CoCl2-4(aq)+6H2O(l) Statement 2: Reaction is endothermic so on cooling, the reaction moves to backward direction (A) If both Statement 1 and Statement 2 are true and the statement 2 is the correct explanation o f the statement 1 . (B) Ifboth Statement 1 and Statement 2 are true but statement 2 is not the correct explanation o f the statement 1 . (C) If Statement 1 is true but Statement 2 is false. (D) If Statement 1 is false but Statement 2 is true.

Tardigrade Admin · Accepted Answer

Both statements are true and statement 2 is the correct explanation of statement 1. Co(H2O)2+6 + (Pink) while CoCl2-4 (blue). So, on cooling because of Le-Chatelier’ s principle the reaction tries to overcome the effect of temperature.

Q. Statement 1: On cooling a freezing mixture, colour of the mixture turns to pink from deep blue for a reaction. Co(H2​O)62+​(aq)+4Cl−(aq)⇌CoCl42−​(aq)+6H2​O(l)​ Statement 2: Reaction is endothermic so on cooling, the reaction moves to backward direction

If both Statement 1 and Statement 2 are true and the statement 2 is the correct explanation o f the statement 1 .

Ifboth Statement 1 and Statement 2 are true but statement 2 is not the correct explanation o f the statement 1 .

If Statement 1 is true but Statement 2 is false.

If Statement 1 is false but Statement 2 is true.

Both statements are true and statement 2 is the correct explanation of statement 1. Co(H2​O)62+​ + (Pink) while CoCl42−​ (blue). So, on cooling because of Le-Chatelier’ s principle the reaction tries to overcome the effect of temperature.

Both statements are true and statement 2 is the correct explanation of statement 1. $C o (H_{2} O)_{6}^{2 +}$ + (Pink) while $C o C l_{4}^{2 -}$ (blue). So, on cooling because of Le-Chatelier’ s principle the reaction tries to overcome the effect of temperature.