Statement 1: Heat given out during neutralisation of NaOH and HF is -13.7 kcal / eq. Statement 2: F -ion is more easily hydrated and thus heat of neutralisation of HF and NaOH is more

Question

Statement 1: Heat given out during neutralisation of NaOH and HF is -13.7 kcal / eq. Statement 2: F -ion is more easily hydrated and thus heat of neutralisation of HF and NaOH is more (A) Statement 1 is True, Statement 2 is True; Statement 2 is correct explanation for Statement 1 (B) Statement 1 is True, Statement 2 is True; Statement 2 is not correct explanation for Statement 1 (C) Statement 1 is True, Statement 2 is False (D) Statement 1 is False, Statement 2 is True

Tardigrade Admin · Accepted Answer

Heat of neutralisation of HF and NaOH is -16.4 kcal / eq. due to extensive hydration of F -of NaF on account of its smaller size

Q. Statement 1 : Heat given out during neutralisation of $N a O H$ and $H F$ is $- 13.7 k c a l / e q$ .
Statement 2 : $F^{-}$ ion is more easily hydrated and thus heat of neutralisation of $H F$ and $N a O H$ is more

Statement 1 is True, Statement 2 is True; Statement 2 is correct explanation for Statement 1

Statement 1 is True, Statement 2 is True; Statement 2 is not correct explanation for Statement 1

Statement 1 is True, Statement 2 is False

Statement 1 is False, Statement 2 is True

Heat of neutralisation of $H F$ and $N a O H$ is $- 16.4 k c a l / e q$ . due to extensive hydration of $F^{-}$ of $N a F$ on account of its smaller size

Q. Statement 1 : Heat given out during neutralisation of NaOH and HF is −13.7kcal/eq. Statement 2 : F−ion is more easily hydrated and thus heat of neutralisation of HF and NaOH is more