1. Tardigrade
  2. Question
  3. Chemistry
  4. Statement 1: Heat given out during neutralisation of NaOH and HF is -13.7 kcal / eq. Statement 2: F -ion is more easily hydrated and thus heat of neutralisation of HF and NaOH is more

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Q. Statement 1 : Heat given out during neutralisation of $NaOH$ and $HF$ is $-13.7\, kcal / eq$.
Statement 2 : $F ^{-}$ion is more easily hydrated and thus heat of neutralisation of $HF$ and $NaOH$ is more

Equilibrium

Solution:

Heat of neutralisation of $HF$ and $NaOH$ is $-16.4 \,kcal / eq$. due to extensive hydration of $F ^{-}$of $NaF$ on account of its smaller size