Question

Statement 1: $[Fe(H_{2}O{)}_{5}NO]S{O}_4$ is paramagnetic.
Statement 2:The $Fe$ in $[Fe(H_{2}O{)}_{5}NO]S{O}_4$ has three impaired electrons.

• A. If both Statement 1 and Statement 2 are true and the statement 2 is the correct explanation o f the statement 1.
• B. Ifboth Statement 1 and Statement 2 are true but statement 2 is not the correct explanation of the statement 1.
• C. If Statement 1 is true but Statement 2 is false.
• D. If Statement 1 is false but Statement 2 is true.

Answer 1

Answer: (A)

Iron in $[Fe(H_{2}O)5NO]S{O}_4$ exists in +2 oxidation state having electronic configuration $(3d{)}^6$. The unpaired electron of $NO$ is shifted to $F{e}^{2+}$ changing it to $F{e}^{+}$ and also changes $NO$ to $N{O}^{+}$. The electronic configuration of iron in the complex thus becomes $(3d{)}^7$ with three unpaired electrons as in the complex, $s{p}^3{d}^2$ hybridization exists.