Statement 1: Equivalent mass of KMnO 4 is equal to one third of its molecular mass when it acts as an oxidising agent in an alkaline medium Statement 2: Oxidation number of Mn is +7 in KMnO 4

Question

Statement 1: Equivalent mass of KMnO 4 is equal to one third of its molecular mass when it acts as an oxidising agent in an alkaline medium Statement 2: Oxidation number of Mn is +7 in KMnO 4 (A) Statement 1 is True, Statement 2 is True; Statement 2 is correct explanation for Statement 1 (B) Statement 1 is True, Statement 2 is True; Statement 2 is not correct explanation for Statement 1 (C) Statement 1 is True, Statement 2 is False (D) Statement 1 is False, Statement 2 is True

Tardigrade Admin · Accepted Answer

In alkaline medium, KMnO 4 is reduced to MnO 2 which involves 3 e- Thus, its eq. wt =(M/3)

Q. Statement 1: Equivalent mass of $K M n O_{4}$ is equal to one third of its molecular mass when it acts as an oxidising agent in an alkaline medium
Statement 2: Oxidation number of $M n$ is $+ 7$ in $K M n O_{4}$

Statement 1 is True, Statement 2 is True; Statement 2 is correct explanation for Statement 1

Statement 1 is True, Statement 2 is True; Statement 2 is not correct explanation for Statement 1

Statement 1 is True, Statement 2 is False

Statement 1 is False, Statement 2 is True

In alkaline medium, $K M n O_{4}$ is reduced to $M n O_{2}$ which involves $3 e^{-}$
Thus, its eq. wt $= \frac{M}{3}$

Q. Statement 1: Equivalent mass of KMnO4​ is equal to one third of its molecular mass when it acts as an oxidising agent in an alkaline medium Statement 2: Oxidation number of Mn is +7 in KMnO4​