Statement 1: Acetic acid on reaction with hydrazoic acid (N3H) in the presence of H2SO4 followed by heating and hydrolysis in basic medium gives acetamide. Statement 2: Methyl isocyanate (Me - N = C = O) is formed as an intermediate compound.

Question

Statement 1: Acetic acid on reaction with hydrazoic acid (N3H) in the presence of H2SO4 followed by heating and hydrolysis in basic medium gives acetamide. Statement 2: Methyl isocyanate (Me - N = C = O) is formed as an intermediate compound. (A) If both Statement 1 and Statement 2 are true and the statement 2 is the correct explanation of the statement 1. (B) If both Statement 1 and Statement 2 are true but statement 2 is not the correct explanation of the statement 1. (C) If Statement 1 is true but Statement 2 is false. (D) If Statement 1 is false but Statement 2 is true.

Tardigrade Admin · Accepted Answer

The product is MeNH2 (methyl amine). It is an example of Claisen-Schmidt rearrangement reaction.

Q. Statement 1: Acetic acid on reaction with hydrazoic acid $(N_{3} H)$ in the presence of $H_{2} S O_{4}$ followed by heating and hydrolysis in basic medium gives acetamide.
Statement 2: Methyl isocyanate $(M e - N = C = O)$ is formed as an intermediate compound.

If both Statement 1 and Statement 2 are true and the statement 2 is the correct explanation of the statement 1.

If both Statement 1 and Statement 2 are true but statement 2 is not the correct explanation of the statement 1.

If Statement 1 is true but Statement 2 is false.

If Statement 1 is false but Statement 2 is true.

The product is $M e N H_{2}$ (methyl amine). It is an example of Claisen-Schmidt rearrangement reaction.

Q. Statement 1: Acetic acid on reaction with hydrazoic acid (N3​H) in the presence of H2​SO4​ followed by heating and hydrolysis in basic medium gives acetamide. Statement 2: Methyl isocyanate (Me−N=C=O) is formed as an intermediate compound.