Starting with the same initial conditions, an ideal gas expands from volume V 1 to V 2 in three different ways. The work done by the gas is W1 if the process is purely isothermal. W2. if the process is purely adiabatic and W 3 if the process is purely isobaric. Then, choose the coned option

Question

Starting with the same initial conditions, an ideal gas expands from volume V 1 to V 2 in three different ways. The work done by the gas is W1 if the process is purely isothermal. W2. if the process is purely adiabatic and W 3 if the process is purely isobaric. Then, choose the coned option (A) W 1< W 2< W 3 (B) W 2< W 3< W 1 (C) W 3< W 1< W 2 (D) W 2< W 1< W 3

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/b60b1fe05246f1d9a0483f9c03390f30-.png" /> Area under curve is work W 2< W 1< W 3

$W_{1} < W_{2} < W_{3}$

$W_{2} < W_{3} < W_{1}$

$W_{3} < W_{1} < W_{2}$

$W_{2} < W_{1} < W_{3}$

Area under curve is work
$W_{2} < W_{1} < W_{3}$

W1​<W2​<W3​

W2​<W3​<W1​

W3​<W1​<W2​

W2​<W1​<W3​

Area under curve is work W2​<W1​<W3​

$W_{1} < W_{2} < W_{3}$

$W_{2} < W_{3} < W_{1}$

$W_{3} < W_{1} < W_{2}$

$W_{2} < W_{1} < W_{3}$

Area under curve is work
$W_{2} < W_{1} < W_{3}$