Standard state Gibbs free energy change for isomerisation reaction, cis-2-pentene trans-2-pentene is -3.67 kJ/mol at 400 K. If more tran5-2-pentene is added to the reaction vessel, then

Question

Standard state Gibbs free energy change for isomerisation reaction, cis-2-pentene trans-2-pentene is -3.67 kJ/mol at 400 K. If more tran5-2-pentene is added to the reaction vessel, then (A) more cis-2-pentene is formed (B) additional frans-2-pentene is formed (C) equilibrium remains unaffected (D) equilibrium is shifted in the forward direction

Tardigrade Admin · Accepted Answer

Δ Go=-ve; If we add frans-2-pentene, equilibrium is displaced in the direction of less trans-2-pentene (Le-chatelier principle).

Q. Standard state Gibbs free energy change for isomerisation reaction, cis-2-pentene trans-2-pentene is -3.67 kJ/mol at 400 K. If more tran5-2-pentene is added to the reaction vessel, then

more cis-2-pentene is formed

additional frans-2-pentene is formed

equilibrium remains unaffected

equilibrium is shifted in the forward direction

$Δ G^{o} = - v e;$ If we add frans-2-pentene, equilibrium is displaced in the direction of less trans-2-pentene (Le-chatelier principle).

Q. Standard state Gibbs free energy change for isomerisation reaction, cis-2-pentene trans-2-pentene is -3.67 kJ/mol at 400 K. If more tran5-2-pentene is added to the reaction vessel, then

more cis-2-pentene is formed

additional frans-2-pentene is formed

equilibrium remains unaffected

equilibrium is shifted in the forward direction

ΔGo=−ve; If we add frans-2-pentene, equilibrium is displaced in the direction of less trans-2-pentene (Le-chatelier principle).

$Δ G^{o} = - v e;$ If we add frans-2-pentene, equilibrium is displaced in the direction of less trans-2-pentene (Le-chatelier principle).