Standard enthalpy and standard entropy changes for the oxidation of ammonia at 298 K are -382.64 kJ mol -1 and -145.6 J K -1 mol -1, respectively. Standard Gibbs energy change for the same reaction at 298 K is

Question

Standard enthalpy and standard entropy changes for the oxidation of ammonia at 298 K are -382.64 kJ mol -1 and -145.6 J K -1 mol -1, respectively. Standard Gibbs energy change for the same reaction at 298 K is (A)  -2221.1kJ mol-1  (B)  -339.3 kJ mol-1  (C)  -439.3 kJ mol-1  (D)  -523.2 kJ mol-1

Tardigrade Admin · Accepted Answer

For the oxidation of ammonia at 298 K the standard enthalpy change (Δ H) and standard entropy change (Δ S) are -382.64 kJ mol -1 and -145.6 JK -1 mol -1 respectively. The relationship of Gibbs free energy (Δ G) with Δ H and Δ S is represented in form of following equation. Δ G=Δ H-T ⋅ Δ S Given that Δ H =-382.64 kJ mol -1 Δ S =-145.6 J K -1 mol -1 =-145.6 × 10-3 kJ K -1 or Δ G =-382.64-(298 ×-145.6 × 10-3) =-339.3 kJ mol -1

Q. Standard enthalpy and standard entropy changes for the oxidation of ammonia at $298 K$ are $- 382.64 k J m o l^{- 1}$ and $- 145.6 J K^{- 1} m o l^{- 1}$ , respectively. Standard Gibbs energy change for the same reaction at $298 K$ is

$- 2221.1 k J m o l^{- 1}$

$- 339.3 k J m o l^{- 1}$

$- 439.3 k J m o l^{- 1}$

$- 523.2 k J m o l^{- 1}$

Q. Standard enthalpy and standard entropy changes for the oxidation of ammonia at 298K are −382.64kJmol−1 and −145.6JK−1mol−1, respectively. Standard Gibbs energy change for the same reaction at 298K is

−2221.1kJmol−1

−339.3kJmol−1

−439.3kJmol−1

−523.2kJmol−1

Q. Standard enthalpy and standard entropy changes for the oxidation of ammonia at $298 K$ are $- 382.64 k J m o l^{- 1}$ and $- 145.6 J K^{- 1} m o l^{- 1}$ , respectively. Standard Gibbs energy change for the same reaction at $298 K$ is

$- 2221.1 k J m o l^{- 1}$

$- 339.3 k J m o l^{- 1}$

$- 439.3 k J m o l^{- 1}$

$- 523.2 k J m o l^{- 1}$