Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
Standard deviation 3,5,7,9,11,13 is
Q. Standard deviation
3
,
5
,
7
,
9
,
11
,
13
is
1709
201
Report Error
A
3
35
B
11
C
11.66
D
3.4
Solution:
Mean
=
8
S
.
D
⋅
=
σ
=
n
1
∑
x
1
2
−
(
x
ˉ
)
2
=
6
454
−
(
8
)
2
=
3
35
∴
S
.
D
⋅
=
3
35