Space waves are used for line-of-sight (LOS) communication as well as satellite communication. Because of line-of-sight nature of propagation, direct waves gets blocked at some point by the curvature of the earth as illustrated in figure. If the signal is to be received beyond the horizon then the receiving antenna must be high enough to intercept the line-of-sight waves. If the transmitting antenna is at a height hT, the distance to the horizon dT is given as

Question

Space waves are used for line-of-sight (LOS) communication as well as satellite communication. Because of line-of-sight nature of propagation, direct waves gets blocked at some point by the curvature of the earth as illustrated in figure. If the signal is to be received beyond the horizon then the receiving antenna must be high enough to intercept the line-of-sight waves. <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/2d34fa9711361709c7ec8a51dcb6e8d7-.png" /> If the transmitting antenna is at a height hT, the distance to the horizon dT is given as (A) dT=√2 h RT (B) dT=√2 R hT (C) dT=2 R hT (D) dT=2 R hT(1+(h r/2 R))

Tardigrade Admin · Accepted Answer

Correct answer is (b) dT=√2 R hT

$d_{T} = 2 h R_{T}$

$d_{T} = 2 R h_{T}$

$d_{T} = 2 R h_{T}$

$d_{T} = 2 R h_{T} (1 + \frac{h r}{2 R})$

Correct answer is (b) $d_{T} = 2 R h_{T}$

dT​=2hRT​​

dT​=2RhT​​

dT​=2RhT​

dT​=2RhT​(1+2Rhr​)

Correct answer is (b) dT​=2RhT​​

$d_{T} = 2 h R_{T}$

$d_{T} = 2 R h_{T}$

$d_{T} = 2 R h_{T}$

$d_{T} = 2 R h_{T} (1 + \frac{h r}{2 R})$

Correct answer is (b) $d_{T} = 2 R h_{T}$