Question

Solve the inequality $\frac{2x-5\le (4x-7)}{3}$ ?

• A. $x\in (-\infty ,4)$
• B. $x\in (-\infty ,4]$
• C. $x\in (-\infty ,8]$
• D. $x\in (-\infty ,-4]$

Answer 1

Answer: (B)

Given, $2x-5\le \frac{(4x-7)}{3}$
$\Rightarrow$ $6x-15\le 4x-7$
$\Rightarrow$ $6x-4x\le -7+15$
$\Rightarrow$ $2x\le 8$
$\Rightarrow$ $x\le \frac{8}{2}\Rightarrow x\le 4$
$\therefore$ $x\in (-\infty ,4]$