Solubility of Mg ( OH )2 in 0.1 M CH 3 COONa is [Ks p. of Mg ( OH )2=1.8 × 10-11, Ka( CH 3 COOH )=1.8 x .10-5, P ka=4.74]

Question

Solubility of Mg ( OH )2 in 0.1 M CH 3 COONa is [Ks p. of Mg ( OH )2=1.8 × 10-11, Ka( CH 3 COOH )=1.8 x .10-5, P ka=4.74] (A) 0.33 M (B) 0.66 M (C) 1.0 × 10-2 M (D) 1.8 × 10-3 M

Tardigrade Admin · Accepted Answer

Aqueous solution of CH 3 COONa is basic due to hydrolysis of CH 3 COO - CH 3 COO -( aq )+ H 2 O leftharpoons CH 3 COOH ( aq )+ OH -( aq ) pH =7+(p Ka/2)+( log C/2) =7+(4.74/2)+( log 0.1/2)=8.87 ∴ pOH =14-8.87=5.13 [ OH ]=10- pOH =10-5.13=10-6 100.87 =7.4 × 10-6 M Let, solubility of Mg ( OH )2= x in 0.1 M CH 3 COO Na Mg ( OH )2( s ) leftharpoons Mg 2+( aq )+2 OH -( aq ) Ks p=[ Mg 2+][ OH ]2 1.8 × 10-11=( x )(7.4 × 10-6)2 x=0.33 M

Q. Solubility of $M g (O H)_{2}$ in $0.1 M C H_{3} COON a$ is $[K_{s p}$ of $M g (O H)_{2} = 1.8 \times 1 0^{- 11}, K_{a} (C H_{3} COO H) = 1.8 x$ $1 0^{- 5}, P k_{a} = 4.74]$

0.33 M

0.66 M

$1.0 \times 1 0^{- 2} M$

$1.8 \times 1 0^{- 3} M$

Q. Solubility of Mg(OH)2​ in 0.1MCH3​COONa is [Ksp​ of Mg(OH)2​=1.8×10−11,Ka​(CH3​COOH)=1.8x 10−5,Pka​=4.74]

0.33 M

0.66 M

1.0×10−2M

1.8×10−3M

Q. Solubility of $M g (O H)_{2}$ in $0.1 M C H_{3} COON a$ is $[K_{s p}$ of $M g (O H)_{2} = 1.8 \times 1 0^{- 11}, K_{a} (C H_{3} COO H) = 1.8 x$ $1 0^{- 5}, P k_{a} = 4.74]$

$1.0 \times 1 0^{- 2} M$

$1.8 \times 1 0^{- 3} M$