Sodium oxide reacts with water to produce sodium hydroxide. 20.0 g of sodium oxide is dissolved in 500 mL of water. Neglecting the change in volume, the concentration of the resulting NaOH solution is × 10-1 M . (Nearest integer) [Atomic mass: Na =23.0, O =16.0, H =1.0 ]

Question

Sodium oxide reacts with water to produce sodium hydroxide. 20.0 g of sodium oxide is dissolved in 500 mL of water. Neglecting the change in volume, the concentration of the resulting NaOH solution is × 10-1 M . (Nearest integer) [Atomic mass: Na =23.0, O =16.0, H =1.0 ] (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Na 2 O + H 2 O arrow 2 NaOH (20/62) moles Moles of NaOH formed =(20/62) × 2 [ NaOH ]=((40/62)/(500)1000)=1.29 M =13 × 10-1 M (Nearest integer)

Q. Sodium oxide reacts with water to produce sodium hydroxide. 20.0g of sodium oxide is dissolved in 500mL of water. Neglecting the change in volume, the concentration of the resulting NaOH solution is ________ ×10−1M. (Nearest integer) [Atomic mass: Na=23.0,O=16.0,H=1.0 ]

Na2​O+H2​O→2NaOH 6220​ moles Moles of NaOH formed =6220​×2 [NaOH]=1000500​6240​​=1.29M =13×10−1M (Nearest integer)

$N a_{2} O + H_{2} O \to 2 N a O H$
$\frac{20}{62}$ moles
Moles of $N a O H$ formed $= \frac{20}{62} \times 2$
$[N a O H] = \frac{\frac{40}{62}}{\frac{500}{1000}} = 1.29 M$
$= 13 \times 1 0^{- 1} M$
(Nearest integer)