SnCl4+2FeCl2 xrightarrow[]SnCl2+2FeCl3 In this reaction, oxidising agent and reducing agent are respectively

Question

SnCl4+2FeCl2 xrightarrow[]SnCl2+2FeCl3 In this reaction, oxidising agent and reducing agent are respectively (A)  SnCl2 and FeCl3  (B)  FeCl3 and SnCl4  (C)  FeCl2 and SnCl4  (D)  SnCl4 and FeCl3

Tardigrade Admin · Accepted Answer

Hence, SnCl4 is oxidising agent while FeCl2 is reducing agent.

Q. $S n C l_{4} + 2 F e C l_{2} S n C l_{2} + 2 F e C l_{3}$ In this reaction, oxidising agent and reducing agent are respectively

$S n C l_{2}$ and $F e C l_{3}$

$F e C l_{3}$ and $S n C l_{4}$

$F e C l_{2}$ and $S n C l_{4}$

$S n C l_{4}$ and $F e C l_{3}$

Hence, $S n C l_{4}$ is oxidising agent while $F e C l_{2}$ is reducing agent.

Q. SnCl4​+2FeCl2​​SnCl2​+2FeCl3​ In this reaction, oxidising agent and reducing agent are respectively

SnCl2​ and FeCl3​

FeCl3​ and SnCl4​

FeCl2​ and SnCl4​

SnCl4​ and FeCl3​