Smallest internuclear distance is found in

Question

Smallest internuclear distance is found in (A) O 2 (B) O 2+2 (C) O 2- (D) O 2-2

Tardigrade Admin · Accepted Answer

In O 2, the bond order =2 In O 2+, the bond order =2.5 In O 2-, the bond order =1.5 In O 2-2, the bond order =1 As the bond order in O 2 + is highest, so its internuclear distance is smallest.

Q. Smallest internuclear distance is found in

$O_{2}$

$O_{2}^{+ 2}$

$O_{2}^{-}$

$O_{2}^{- 2}$

In $O_{2}$ , the bond order $= 2$

In $O_{2}^{+}$ , the bond order $= 2.5$

In $O_{2}^{-}$ , the bond order $= 1.5$

In $O_{2}^{- 2}$ , the bond order $= 1$

As the bond order in $O_{2}^{+}$ is highest,

so its internuclear distance is smallest.

Q. Smallest internuclear distance is found in

O2​

O2+2​

O2−​

O2−2​

In O2​, the bond order =2 In O2+​, the bond order =2.5 In O2−​, the bond order =1.5 In O2−2​, the bond order =1 As the bond order in O2​+ is highest, so its internuclear distance is smallest.

$O_{2}$

$O_{2}^{+ 2}$

$O_{2}^{-}$

$O_{2}^{- 2}$

In $O_{2}$ , the bond order $= 2$

In $O_{2}^{+}$ , the bond order $= 2.5$

In $O_{2}^{-}$ , the bond order $= 1.5$

In $O_{2}^{- 2}$ , the bond order $= 1$

As the bond order in $O_{2}^{+}$ is highest,

so its internuclear distance is smallest.