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Chemistry
Smallest internuclear distance is found in
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Q. Smallest internuclear distance is found in
AIIMS
AIIMS 2001
Chemical Bonding and Molecular Structure
A
$O _{2}$
16%
B
$O _{2}^{+2}$
57%
C
$O _{2}^{-}$
13%
D
$O _{2}^{-2}$
13%
Solution:
In $O _{2}$, the bond order $=2$
In $O _{2}^{+}$, the bond order $=2.5$
In $O _{2}^{-}$, the bond order $=1.5$
In $O _{2}^{-2}$, the bond order $=1$
As the bond order in $O _{2}{ }^{+}$ is highest,
so its internuclear distance is smallest.