Six moles of an ideal gas performs a cycle shown in figure. If the temperature are TA = 600 K, TB = 800 K, TC = 2200 K and TD = 1200 K, the work done per cycle is approximately

Question

Six moles of an ideal gas performs a cycle shown in figure. If the temperature are TA = 600 K, TB = 800 K, TC = 2200 K and TD = 1200 K, the work done per cycle is approximately (A) 20 kJ (B) 30 kJ (C) 40 kJ (D) 60 kJ

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/be5ece08fedeed13d286378c5a3df324-.png" /> Processes A to B and C to D are parts of straight line graphs passing through origin P ∝T. So, volume remains constant for the graph AB and CD So, no work is done during processes for A to B and C to D i.e., WAB = WCD = 0 and WBC = P2(VC - VB) = nR(TC - TB) = 6R(2200 - 800) = 6R ×1400 J Also, WDA = P1(VA - VD) = nR(TA - TD) = 6R(600 - 1200) = - 6R ×600 J Hence, work done in complete cycle W = WAB + WBC + WCD + WDA = 0+ 6R ×1400 + 0 - 6R ×600 = 6R ×800 = 6 ×8.3 × 800 = 40 kJ

Q. Six moles of an ideal gas performs a cycle shown in figure. If the temperature are $T_{A} = 600 K, T_{B} = 800 K, T_{C} = 2200 K$ and $T_{D} = 1200 K$ , the work done per cycle is approximately

$20 k J$

$30 k J$

$40 k J$

$60 k J$

Q. Six moles of an ideal gas performs a cycle shown in figure. If the temperature are TA​=600K,TB​=800K,TC​=2200K and TD​=1200K, the work done per cycle is approximately

20kJ

30kJ

40kJ

60kJ

Q. Six moles of an ideal gas performs a cycle shown in figure. If the temperature are $T_{A} = 600 K, T_{B} = 800 K, T_{C} = 2200 K$ and $T_{D} = 1200 K$ , the work done per cycle is approximately

$20 k J$

$30 k J$

$40 k J$

$60 k J$