Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
sin x = (2pq/p2 + q2) ⇒ cos ecx + cot x =
Q.
sin
x
=
p
2
+
q
2
2
pq
⇒
cos
ec
x
+
cot
x
=
1377
185
Trigonometric Functions
Report Error
A
q
p
35%
B
p
q
18%
C
q
2
p
33%
D
p
2
q
14%
Solution:
Use
(
sin
2
θ
+
cos
2
θ
)
=
1