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Tardigrade
Question
Mathematics
sin ((5 π/3))+ sec ((13 π/3))=
Q.
sin
(
3
5
π
)
+
sec
(
3
13
π
)
=
2388
207
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A
2
−
2
3
0%
B
2
+
2
3
0%
C
3
+
2
1
100%
D
3
−
2
1
0%
Solution:
sin
(
3
5
π
)
+
sec
(
3
13
π
)
=
sin
(
2
π
−
3
π
)
+
sec
(
4
π
+
3
π
)
=
−
sin
3
π
+
sec
3
π
=
−
2
3
+
2
=
2
−
2
3