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Tardigrade
Question
Mathematics
sin 120° cos 150°- cos 240° sin 330° is equal to :
Q.
sin
12
0
∘
cos
15
0
∘
−
cos
24
0
∘
sin
33
0
∘
is equal to :
2162
174
EAMCET
EAMCET 2006
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A
1
B
-1
C
3
2
D
−
(
4
3
+
1
)
Solution:
sin
12
0
∘
cos
15
0
∘
−
cos
24
0
∘
sin
33
0
∘
=
−
cos
3
0
∘
sin
6
0
∘
−
cos
6
0
∘
sin
3
0
∘
=
−
(
sin
6
0
∘
cos
3
0
∘
+
cos
6
0
∘
sin
3
0
∘
)
=
−
sin
(
6
0
∘
+
3
0
∘
)
=
−
sin
9
0
∘
=
−
1