Simple pendulum of large length is made equal to the radius of the earth. Its period of oscillation will be :

Question

Simple pendulum of large length is made equal to the radius of the earth. Its period of oscillation will be : (A) 84.6 min. (B) 59.8 min. (C) 42.3 min. (D) 21.15 min

Tardigrade Admin · Accepted Answer

T =2 π √(1/ g ((1) R +(1) R ) ⇒ T =2 π √( R /2 g )=(84.6/√2) min or T =59.8 min

Q. Simple pendulum of large length is made equal to the radius of the earth. Its period of oscillation will be :

84.6 min.

59.8 min.

42.3 min.

21.15 min

$T = 2 π \frac{1}{g ( \frac{1}{R} + \frac{1}{R} )}$
$\Rightarrow T = 2 π \frac{R}{2 g} = \frac{84.6}{2} min$
or $T = 59.8 min$

Q. Simple pendulum of large length is made equal to the radius of the earth. Its period of oscillation will be :

84.6 min.

59.8 min.

42.3 min.

21.15 min

T=2πg(R1​+R1​)1​​ ⇒T=2π2gR​​=2​84.6​min or T=59.8min

$T = 2 π \frac{1}{g ( \frac{1}{R} + \frac{1}{R} )}$
$\Rightarrow T = 2 π \frac{R}{2 g} = \frac{84.6}{2} min$
or $T = 59.8 min$