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  4. Simple pendulum of large length is made equal to the radius of the earth. Its period of oscillation will be :

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Q. Simple pendulum of large length is made equal to the radius of the earth. Its period of oscillation will be :

Oscillations

Solution:

$T =2 \pi \sqrt{\frac{1}{ g \left(\frac{1}{ R }+\frac{1}{ R }\right)}} $
$\Rightarrow T =2 \pi \sqrt{\frac{ R }{2 g }}=\frac{84.6}{\sqrt{2}} \min$
or $T =59.8\, \min$