Silver chloride dissolves in excess of ammonium hydroxide solution. The cation present in the resulting solution is

Question

Silver chloride dissolves in excess of ammonium hydroxide solution. The cation present in the resulting solution is (A) [Ag(NH3)6]+ (B) [Ag(NH3)4]+ (C) Ag+ (D) [Ag(NH3)2]+

Tardigrade Admin · Accepted Answer

[A g (N H_{3})_{2}]^{+}

In aqueous solution, silver chloride exist as

A g^{+}

and

C l^{-} A g^{+}

present in solution reacts with

N H_{3}

to form

[A g (N H_{3})_{2}]^{+}

.

A g^{+} C l^{-} + 2 N H_{3} ⟶ [A g (N H_{3})_{2}]^{+} C l^{-}

Q. Silver chloride dissolves in excess of ammonium hydroxide solution. The cation present in the resulting solution is

$[A g (N H_{3})_{6}]^{+}$

$[A g (N H_{3})_{4}]^{+}$

$A g^{+}$

$[A g (N H_{3})_{2}]^{+}$

Q. Silver chloride dissolves in excess of ammonium hydroxide solution. The cation present in the resulting solution is

[Ag(NH3​)6​]+

[Ag(NH3​)4​]+

Ag+

[Ag(NH3​)2​]+

$[A g (N H_{3})_{6}]^{+}$

$[A g (N H_{3})_{4}]^{+}$

$A g^{+}$

$[A g (N H_{3})_{2}]^{+}$