Silica reacts with Hydride of superhalogen to form 'X'. On hydrolysis of 'X' another compound 'Y' is formed. 'Y' on heating at 1000° C loses water to form ' Z '. The 'Z' can also be prepared in the following reaction.

Question

Silica reacts with Hydride of superhalogen to form 'X'. On hydrolysis of 'X' another compound 'Y' is formed. 'Y' on heating at 1000° C loses water to form ' Z '. The 'Z' can also be prepared in the following reaction. (A) SiO 2+4 HF arrow SiF 4+2 H 2 O (B) Si + O 2 arrow SiO 2 (C) K 2 SiF 6+4 K arrow 6 KF + Si (D) Si +2 NaOH + H 2 O arrow Na 2 SiO 3+2 H 2

Tardigrade Admin · Accepted Answer

Hydride of super halogen = HF SiO 2+4 HF arrow underset(X)SiF 4+2 H 2 O 3 SiF 4+4 H 2 O arrow underset(Y)H 4 SiO 4+2 H 2 SiF 6 H 4 SiO 4 stackrel1000° C longrightarrow underset(Z)SiO 2+2 H 2 O X = SiF 4, Y = H 4 SiO 4, Z = SiO 2 Si + O 2 arrow SiO

Q. Silica reacts with Hydride of superhalogen to form $^{'} X^{'} .$ On hydrolysis of $^{'} X^{'}$ another compound $^{'} Y^{'}$ is formed. $^{'} Y^{'}$ on heating at $100 0^{\circ} C$ loses water to form ' $Z$ '. The $^{'} Z^{'}$ can also be prepared in the following reaction.

$S i O_{2} + 4 H F \to S i F_{4} + 2 H_{2} O$

$S i + O_{2} \to S i O_{2}$

$K_{2} S i F_{6} + 4 K \to 6 K F + S i$

$S i + 2 N a O H + H_{2} O \to N a_{2} S i O_{3} + 2 H_{2}$

Hydride of super halogen $= H F$

$S i O_{2} + 4 H F \to (X) S i F_{4} + 2 H_{2} O$

$3 S i F_{4} + 4 H_{2} O \to (Y) H_{4} S i O_{4} + 2 H_{2} S i F_{6}$

$H_{4} S i O_{4} ⟶ 100 0^{\circ} C (Z) S i O_{2} + 2 H_{2} O$

$X = S i F_{4}, Y = H_{4} S i O_{4}, Z = S i O_{2}$

$S i + O_{2} \to S i O$

Q. Silica reacts with Hydride of superhalogen to form ′X′. On hydrolysis of ′X′ another compound ′Y′ is formed. ′Y′ on heating at 1000∘C loses water to form ' Z '. The ′Z′ can also be prepared in the following reaction.

SiO2​+4HF→SiF4​+2H2​O

Si+O2​→SiO2​

K2​SiF6​+4K→6KF+Si

Si+2NaOH+H2​O→Na2​SiO3​+2H2​