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Question
Mathematics
sin6A+cos6A+3sin2Acos2A is equal to
Q.
s
i
n
6
A
+
co
s
6
A
+
3
s
i
n
2
A
co
s
2
A
is equal to
1539
197
Rajasthan PET
Rajasthan PET 2002
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A
3
B
2
C
1
D
0
Solution:
s
i
n
6
A
+
co
s
6
A
+
3
s
i
n
2
A
co
s
2
A
=
(
sin
2
A
)
3
+
(
cos
2
A
)
3
+
3
sin
2
A
.
cos
2
A
=
(
sin
2
A
+
cos
2
A
)
(
sin
4
A
.
+
cos
4
A
−
sin
2
A
cos
2
A
)
+
3
sin
2
A
cos
2
A
=
(
sin
2
A
)
2
+
(
cos
2
A
)
2
+
2
sin
2
A
cos
2
A
=
(
sin
2
A
+
cos
2
A
)
2
=
1