Question

Show that any angle in a semicircle is a right angle. The following are the steps involved in showing the above result. Arrange them in sequential order. (A) $\therefore \angle ACB=\frac{180^{\circ }}{2}=90^{\circ }$ (B) The angle subtended by an arc at the centre is double of the angle subtended by the same arc at any point on the remaining part of the circle. (C) Let $AB$ be a diameter of a circle with centre $D$ and $C$ be any point on the circle. Join $AC$ and $BC$. (D) $\therefore \angle ADB=2\times \angle ACB$ $180^{\circ }=2\angle ACB\left(\because \angle ADB=180^{\circ }\right)$

• A. $DBAC$
• B. DBCA
• C. $CBAD$
• D. CBDA

Answer 1

Answer: (D)

$CBDA$ is the required sequential order.