Separation between two parallel plates facing each other is 2 cm and surface area l2=100 cm 2 . If 106 electrons of velocity 108 m / s projected into the gap between plates of potential difference 400 V, the deflection of an electron is

Question

Separation between two parallel plates facing each other is 2 cm and surface area l2=100 cm 2 . If 106 electrons of velocity 108 m / s projected into the gap between plates of potential difference 400 V, the deflection of an electron is (A) 17.6 mm (B) 1.76 mm (C) 0.176 mm (D) zero

Tardigrade Admin · Accepted Answer

The reflection of electron is given by y=0+(1/2) a t2 =(1/2)((e E/m))((l/v))2 =(e E l2/2 m v2)=(e V l2/2 m d v2) =(1.6 × 10-19 × 400 × 10-2/2 × 9.1 × 10-31 × 2 × 10-2 ×(108)2) =0.176 × 10-2 m =0.176 cm =1.76 mm

Q. Separation between two parallel plates facing each other is 2cm and surface area l2=100cm2. If 106 electrons of velocity 108m/s projected into the gap between plates of potential difference 400V, the deflection of an electron is

17.6 mm

1.76 mm

0.176 mm

zero

The reflection of electron is given by y=0+21​at2 =21​(meE​)(vl​)2 =2mv2eEl2​=2mdv2eVl2​ =2×9.1×10−31×2×10−2×(108)21.6×10−19×400×10−2​ =0.176×10−2m =0.176cm=1.76mm

Q. Separation between two parallel plates facing each other is $2 c m$ and surface area $l^{2} = 100 c m^{2} .$ If $1 0^{6}$ electrons of velocity $1 0^{8} m / s$ projected into the gap between plates of potential difference $400 V$ , the deflection of an electron is