Separation between the plates of circular PPC of diameter 40 mm, whose capacity is equal to capacitance of sphere of radius 1 m will be

Question

Separation between the plates of circular PPC of diameter 40 mm, whose capacity is equal to capacitance of sphere of radius 1 m will be (A) 1 mm (B) 10 mm (C) 0.01 mm (D) 0.1 mm

Tardigrade Admin · Accepted Answer

C PPC = C text sphere (ε0 π r2/d)=4 π ε0 R d =(r2/4 R )=((20 × 10-3)2/4) d =10-4 m d =0.1 mm

Q. Separation between the plates of circular PPC of diameter $40 mm,$ whose capacity is equal to capacitance of sphere of radius $1 m$ will be

1 mm

10 mm

0.01 mm

0.1 mm

$C_{PPC} = C_{sphere}$
$\frac{ε _{0} π r ^{2}}{d} = 4 π ε_{0} R$
$d = \frac{r ^{2}}{4 R} = \frac{( 20 \times 1 0 ^{- 3} ) ^{2}}{4}$
$d = 1 0^{- 4} m$
$d = 0.1 mm$

Q. Separation between the plates of circular PPC of diameter 40mm, whose capacity is equal to capacitance of sphere of radius 1m will be