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  4. Separation between the plates of circular PPC of diameter 40 mm, whose capacity is equal to capacitance of sphere of radius 1 m will be

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Q. Separation between the plates of circular PPC of diameter $40\, mm,$ whose capacity is equal to capacitance of sphere of radius $1\, m$ will be

Solution:

$C _{ PPC }= C _{\text {sphere }}$
$\frac{\varepsilon_{0} \pi r^{2}}{d}=4 \pi \varepsilon_{0} R$
$d =\frac{r^{2}}{4 R }=\frac{\left(20 \times 10^{-3}\right)^{2}}{4}$
$d =10^{-4}\, m$
$d =0.1\, mm$