sec function (secant function) is not defined for

Question

sec function (secant function) is not defined for (A) even multiple of (π/2) (B) odd multiple of (π/2) (C) even multiple of π (D) odd multiple of π

Tardigrade Admin · Accepted Answer

Since, sec x=(1/ cos x), the domain of y= sec x is the set R- x: x=(2 n+1) (π/2), n ∈ Z and range is the set R-(-1,1). It means that sec (secant function) assumes all real values except -1 < y < 1 and is not defined for odd multiples of (π/2).

Q. sec function (secant function) is not defined for

even multiple of $\frac{π}{2}$

odd multiple of $\frac{π}{2}$

even multiple of $π$

odd multiple of $π$

Since, $sec x = \frac{1}{c o s x}$ , the domain of $y = sec x$ is the set $R - {x : x = (2 n + 1) \frac{π}{2}, n \in Z}$ and range is the set $R - (- 1, 1)$ . It means that sec (secant function) assumes all real values except $- 1 < y < 1$ and is not defined for odd multiples of $\frac{π}{2}$ .

Q. sec function (secant function) is not defined for

even multiple of 2π​

odd multiple of 2π​

even multiple of π

odd multiple of π

Since, secx=cosx1​, the domain of y=secx is the set R−{x:x=(2n+1)2π​,n∈Z} and range is the set R−(−1,1). It means that sec (secant function) assumes all real values except −1<y<1 and is not defined for odd multiples of 2π​.

even multiple of $\frac{π}{2}$

odd multiple of $\frac{π}{2}$

even multiple of $π$

odd multiple of $π$

Since, $sec x = \frac{1}{c o s x}$ , the domain of $y = sec x$ is the set $R - {x : x = (2 n + 1) \frac{π}{2}, n \in Z}$ and range is the set $R - (- 1, 1)$ . It means that sec (secant function) assumes all real values except $- 1 < y < 1$ and is not defined for odd multiples of $\frac{π}{2}$ .