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Tardigrade
Question
Mathematics
sec 50° + tan 50° is equal to
Q.
sec
5
0
∘
+
tan
5
0
∘
is equal to
1892
226
Trigonometric Functions
Report Error
A
t
an
2
0
∘
+
tan
5
0
∘
23%
B
2
tan
2
0
∘
+
tan
5
0
∘
20%
C
tan
2
0
∘
+
2
tan
5
0
∘
46%
D
2
tan
2
0
∘
+
2
tan
5
0
∘
11%
Solution:
Correct answer is (c)
tan
2
0
∘
+
2
tan
5
0
∘