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Mathematics
sec 50° + tan 50° is equal to
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Q. $\sec \, 50^{\circ} + \tan \, 50^{\circ}$ is equal to
Trigonometric Functions
A
$tan \, 20^{\circ} + \tan \, 50^{\circ} $
23%
B
$ 2 \tan \, 20^{\circ} + \tan \, 50^{\circ} $
20%
C
$ \tan \, 20^{\circ} + 2 \tan \, 50^{\circ} $
46%
D
$ 2 \tan \, 20^{\circ} + 2 \tan \, 50^{\circ} $
11%
Solution:
Correct answer is (c) $ \tan \, 20^{\circ} + 2 \tan \, 50^{\circ} $