S (rhombic) + O 2( g ) arrow SO 2( g ) ; Δ H =-297.5 kJ S (monoclinic) + O 2( g ) arrow SO 2( g ) ; Δ H =-300 kJ The above data can predict that

Question

S (rhombic) + O 2( g ) arrow SO 2( g ) ; Δ H =-297.5 kJ S (monoclinic) + O 2( g ) arrow SO 2( g ) ; Δ H =-300 kJ The above data can predict that (A) Rhombic sulphur is yellow in colour, (B) Monoclinic sulphur has metallic lustre (C) Monoclinic sulphur is more stable (D) Δ H text (Transition) of S ( R ) to S ( M ) is endothermic process

Tardigrade Admin · Accepted Answer

S ( rhombic )+ O 2( g ) longrightarrow SO 2( g ); Δ H =-297.5 kJ ... (1) S ( text monoclinic )+ O 2( g ) longrightarrow SO 2( g ) ; Δ H =-300 kJ ... (2) Subtracting (2) from (1), S ( text rhombic ) longrightarrow S ( text monoclinic ); Δ H =(-297.5+300) kJ =+2.5 kJ ⇒ This transition is endothermic.

Q. $S$ (rhombic) $+ O_{2} (g) \to S O_{2} (g); Δ H = - 297.5 k J$
$S$ (monoclinic) $+ O_{2} (g) \to S O_{2} (g); Δ H = - 300 k J$
The above data can predict that

Rhombic sulphur is yellow in colour,

Monoclinic sulphur has metallic lustre

Monoclinic sulphur is more stable

$Δ H_{(Transition)}$ of $S (R)$ to $S (M)$ is endothermic process

Q. S (rhombic) +O2​(g)→SO2​(g);ΔH=−297.5kJ S (monoclinic) +O2​(g)→SO2​(g);ΔH=−300kJ The above data can predict that

Rhombic sulphur is yellow in colour,

Monoclinic sulphur has metallic lustre

Monoclinic sulphur is more stable

ΔH(Transition) ​ of S(R) to S(M) is endothermic process

S(rhombic)​+O2​(g)⟶SO2​(g); ΔH=−297.5kJ ... (1) S(monoclinic )​+O2​(g)⟶SO2​(g); ΔH=−300kJ ... (2) Subtracting (2) from (1), S(rhombic )​⟶S(monoclinic )​; ΔH=(−297.5+300)kJ=+2.5kJ ⇒ This transition is endothermic.

Q. $S$ (rhombic) $+ O_{2} (g) \to S O_{2} (g); Δ H = - 297.5 k J$
$S$ (monoclinic) $+ O_{2} (g) \to S O_{2} (g); Δ H = - 300 k J$
The above data can predict that

$Δ H_{(Transition)}$ of $S (R)$ to $S (M)$ is endothermic process