Rydberg has given the equation for all visible radiation in the hydrogen spectrum as λ =(kn2/n2 - 4) . The value of k in terms of Rydberg constant is :

Question

Rydberg has given the equation for all visible radiation in the hydrogen spectrum as λ =(kn2/n2 - 4) . The value of k in terms of Rydberg constant is : (A) 4R (B) (R/4) (C) (4/R) (D) R

Tardigrade Admin · Accepted Answer

(1/λ )=RZ2[(1/n12) - (1/n22)] (n2 - 4/kn2)=R[(1/22) - (1/n2)] (n2 - 4/k ⋅ n2)=R[(n2 - 4/n2 ⋅ 4)] boxedk = (4/R)

Q. Rydberg has given the equation for all visible radiation in the hydrogen spectrum as $λ = \frac{k n ^{2}}{n ^{2} - 4}$ . The value of $k$ in terms of Rydberg constant is :

$4 R$

$\frac{R}{4}$

$\frac{4}{R}$

$R$

$\frac{1}{λ} = R Z^{2} [\frac{1}{n _{1}^{2}} - \frac{1}{n _{2}^{2}}]$
$\frac{n ^{2} - 4}{k n ^{2}} = R [\frac{1}{2 ^{2}} - \frac{1}{n ^{2}}]$
$\frac{n ^{2} - 4}{k \cdot n ^{2}} = R [\frac{n ^{2} - 4}{n ^{2} \cdot 4}]$
$k = \frac{4}{R}$

Q. Rydberg has given the equation for all visible radiation in the hydrogen spectrum as λ=n2−4kn2​ . The value of k in terms of Rydberg constant is :

4R

4R​

R4​

R

λ1​=RZ2[n12​1​−n22​1​] kn2n2−4​=R[221​−n21​] k⋅n2n2−4​=R[n2⋅4n2−4​] k=R4​​

Q. Rydberg has given the equation for all visible radiation in the hydrogen spectrum as $λ = \frac{k n ^{2}}{n ^{2} - 4}$ . The value of $k$ in terms of Rydberg constant is :

$4 R$

$\frac{R}{4}$

$\frac{4}{R}$

$R$

$\frac{1}{λ} = R Z^{2} [\frac{1}{n _{1}^{2}} - \frac{1}{n _{2}^{2}}]$
$\frac{n ^{2} - 4}{k n ^{2}} = R [\frac{1}{2 ^{2}} - \frac{1}{n ^{2}}]$
$\frac{n ^{2} - 4}{k \cdot n ^{2}} = R [\frac{n ^{2} - 4}{n ^{2} \cdot 4}]$
$k = \frac{4}{R}$