Rydberg given the equation for all visible radiation in the hydrogen spectrum as λ =(kn2/n2 - 4) . The value of k in terms of Rydberg constant is

Question

Rydberg given the equation for all visible radiation in the hydrogen spectrum as λ =(kn2/n2 - 4) . The value of k in terms of Rydberg constant is (A) 4R (B) (R/4) (C) (4/R) (D) R

Tardigrade Admin · Accepted Answer

(1/λ )=R((1/4) - (1/n2)) =R((n2 - 4/4 n2))

Q. Rydberg given the equation for all visible radiation in the hydrogen spectrum as $λ = \frac{k n ^{2}}{n ^{2} - 4}$ . The value of $k$ in terms of Rydberg constant is

$4 R$

$\frac{R}{4}$

$\frac{4}{R}$

$R$

$\frac{1}{λ} = R (\frac{1}{4} - \frac{1}{n ^{2}})$
$= R (\frac{n ^{2} - 4}{4 n ^{2}})$

Q. Rydberg given the equation for all visible radiation in the hydrogen spectrum as λ=n2−4kn2​ . The value of k in terms of Rydberg constant is

4R

4R​

R4​

R

λ1​=R(41​−n21​) =R(4n2n2−4​)

Q. Rydberg given the equation for all visible radiation in the hydrogen spectrum as $λ = \frac{k n ^{2}}{n ^{2} - 4}$ . The value of $k$ in terms of Rydberg constant is

$4 R$

$\frac{R}{4}$

$\frac{4}{R}$

$R$

$\frac{1}{λ} = R (\frac{1}{4} - \frac{1}{n ^{2}})$
$= R (\frac{n ^{2} - 4}{4 n ^{2}})$