Question

Runs scored by a batsman in $10$ innings are: $38,70,48,34,42,55,63,46,54,44$ The mean deviation is

• A. $8.6$
• B. $6.4$
• C. $10.6$
• D. $9.6$

Answer 1

Answer: (A)

Arranging the given data in ascending order, we have
$34,38,42,44,46,48,54,55,63,70,$
Median, $M=\frac{46+48}{2}=47$
($\therefore n=10,$median is the mean of 5th and 6th items)
$\therefore$ Mean deviation $=\frac{\Sigma |x_i-M|}{n}$
$=\frac{\Sigma |x_i-47|}{10}=\frac{13+9+5+3+1+1+7+8+16+23}{10}=8.6$