Rs. 1150 become Rs. 1437.5 at 12 % per annum simple interest. The time will be.

Question

Rs. 1150 become Rs. 1437.5 at 12 % per annum simple interest. The time will be. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Here, mathrmP= Rs. 1150 ; mathrmA= Rs. 1437.5; R 12 % p.a. S.I = mathrmA- mathrmP= mathrmRs .(1437.5-1150)= Rs. 287.5 Let the time be ' mathrmT ' years Then, mathrmT=(100 × mathrmSI/ mathrmP × mathrmR)=(100 × 287.5/1150 × 12)=2.08 %

Q. Rs. 1150 become Rs. 1437.5 at $12%$ per annum simple interest. The time will be.____

Here, $P =$ Rs. $1150; A =$ Rs. 1437.5; R $12%$ p.a. S.I $= A - P = Rs . (1437.5 - 1150) =$ Rs. 287.5
Let the time be ' $T$ ' years
Then, $T = \frac{100 \times SI}{P \times R} = \frac{100 \times 287.5}{1150 \times 12} = 2.08%$

Q. Rs. 1150 become Rs. 1437.5 at 12% per annum simple interest. The time will be.____

Here, P= Rs. 1150;A= Rs. 1437.5; R 12% p.a. S.I =A−P=Rs.(1437.5−1150)= Rs. 287.5 Let the time be ' T ' years Then, T=P×R100×SI​=1150×12100×287.5​=2.08%

Q. Rs. 1150 become Rs. 1437.5 at $12%$ per annum simple interest. The time will be.____

Here, $P =$ Rs. $1150; A =$ Rs. 1437.5; R $12%$ p.a. S.I $= A - P = Rs . (1437.5 - 1150) =$ Rs. 287.5
Let the time be ' $T$ ' years
Then, $T = \frac{100 \times SI}{P \times R} = \frac{100 \times 287.5}{1150 \times 12} = 2.08%$