Resistance of each part is 'R' and resistance of circumference is negligible as shown in figure. The equivalent resistance across AB is (3 R/α ). Fill the value of α .

Question

Resistance of each part is 'R' and resistance of circumference is negligible as shown in figure. The equivalent resistance across AB is (3 R/α ). Fill the value of α . <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-j2aqsznoojtyladj.jpg" /> (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-j2aqsznoojtydkn0.jpg" /> Resistance of each part is R Using symmetry Re q=(R/8)+(R/16)=(3 R/16)

Q. Resistance of each part is $^{'} R^{'}$ and resistance of circumference is negligible as shown in figure. The equivalent resistance across $A B$ is $\frac{3 R}{α} .$ Fill the value of $α .$

Resistance of each part is $R$
Using symmetry
$R_{e q} = \frac{R}{8} + \frac{R}{16} = \frac{3 R}{16}$

Q. Resistance of each part is ′R′ and resistance of circumference is negligible as shown in figure. The equivalent resistance across AB is α3R​. Fill the value of α.

Resistance of each part is R Using symmetry Req​=8R​+16R​=163R​

Q. Resistance of each part is $^{'} R^{'}$ and resistance of circumference is negligible as shown in figure. The equivalent resistance across $A B$ is $\frac{3 R}{α} .$ Fill the value of $α .$

Resistance of each part is $R$
Using symmetry
$R_{e q} = \frac{R}{8} + \frac{R}{16} = \frac{3 R}{16}$