Resistance of 6 ohm each are connected in the manner shown in adjoining figure with the current 0.5 ampere as shown in figure. The potential difference Vp - VQ is

Question

Resistance of 6 ohm each are connected in the manner shown in adjoining figure with the current 0.5 ampere as shown in figure. The potential difference Vp - VQ is <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/a5bc96bd021e7967f33abe7f6c0bdb6f-.png" /> (A) 3.6 V (B) 6 V (C) 3 V (D) 7.2 V

Tardigrade Admin · Accepted Answer

V P - V Q =[(6/3)+(12 × 6/12+6)] × (1/2) =(2+4) (1/2)=3 V

Q. Resistance of $6$ ohm each are connected in the manner shown in adjoining figure with the current $0.5$ ampere as shown in figure. The potential difference $V_{p} - V_{Q}$ is

$3.6 V$

$6 V$

$3 V$

$7.2 V$

$V_{P} - V_{Q} = [\frac{6}{3} + \frac{12 \times 6}{12 + 6}] \times \frac{1}{2}$
$= (2 + 4) \frac{1}{2} = 3 V$

Q. Resistance of 6 ohm each are connected in the manner shown in adjoining figure with the current 0.5 ampere as shown in figure. The potential difference Vp​−VQ​ is

3.6V

6V

3V

7.2V