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  4. Resistance of 6 ohm each are connected in the manner shown in adjoining figure with the current 0.5 ampere as shown in figure. The potential difference Vp - VQ is <img class=img-fluid question-image alt=image src=https://cdn.tardigrade.in/img/question/physics/a5bc96bd021e7967f33abe7f6c0bdb6f-.png />

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Q. Resistance of $6$ ohm each are connected in the manner shown in adjoining figure with the current $0.5$ ampere as shown in figure. The potential difference $V_p - V_Q$ is
image

Current Electricity

Solution:

$V _{ P }- V _{ Q }=\left[\frac{6}{3}+\frac{12 \times 6}{12+6}\right] \times \frac{1}{2}$
$=(2+4) \frac{1}{2}=3 V$