1920
230
Complex Numbers and Quadratic Equations
Report Error
Solution:
Let 1=rcosθ,3=rsinθ
By squaring and adding, we get r2(cos2θ+sin2θ)=4
i.e., r=4=2
Therefore, cosθ=21, sinθ=23,
which gives θ=3π
Therefore, required polar form is z=2(cos3π+isin3π)