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214
Complex Numbers and Quadratic Equations
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Solution:
Let 1=rcosθ,3=rsinθ
By squaring and adding, we get r2(cos2θ+sin2θ)=4
i.e, r=4=2
Therefore, cosθ=21,sinθ=23,
which gives θ=3π
Therefore, required polar form is : z=2(cos3π+isin3π)