Question

Relation between wavelength of photon and electron of same energy is :

• A. ${\lambda }_{ph}>{\lambda }_e$
• B. ${\lambda }_{ph}<{\lambda }_e$
• C. ${\lambda }_{ph}={\lambda }_e$
• D. $\frac{{\lambda }_e}{{\lambda }_{ph}}=$ constant

Answer 1

Answer: (A)

Wavelength $\lambda =\frac{hc}{p}\{p=\sqrt{2mE}\}$
$\therefore \lambda =\frac{hc}{\sqrt{2mE}}$
$\therefore \lambda \propto \frac{1}{\sqrt{m}}$
Mass of photon is less than that of electron.
$\therefore$ wavelength of photon is greater than that of electron ${\lambda }_{ph}>{\lambda }_e$